Comparing E471 - Mono- and diglycerides of fatty acids vs E916 - Calcium iodate
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Found in 26,595 products
Found in 308 products
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Interest over time for 9 keywords in U.S. during the last 10 years.
Interest over time for 2 keywords in U.S. during the last 10 years.
Popular questions
Are mono and diglycerides bad for you?
They are widely used emulsifiers and are considered safe at typical food levels (e.g., GRAS in the U.S.; JECFA ADI “not specified”). Their main nutritional impact is a small addition of fat/calories.
Is mono and diglycerides pork?
Not by definition—they’re fat-derived emulsifiers that can come from plant oils or animal fats, including pork. Check the manufacturer or look for vegetarian/halal/kosher claims to know the source.
Are mono and diglycerides halal?
They can be halal if made from plant oils or from halal-slaughtered animal fat; if sourced from non‑halal animal fats (e.g., pork), they are not halal. Choose halal‑certified products to be sure.
Are mono and diglycerides vegan?
Not always—E471 may be made from plant oils or animal fats. Look for labels stating “vegetable mono- and diglycerides” or vegan certification.
What is mono and diglycerides made from?
They’re produced by reacting glycerol with edible fats/oils (plant or animal) to form partial glycerides. Common fatty acids include stearic, palmitic, and oleic acid.
How to calculate calcium iodate solubility in potassium iodate solution?
Use the dissolution Ca(IO3)2(s) ⇌ Ca2+ + 2 IO3− and Ksp = [Ca2+][IO3−]^2; with initial iodate C from KIO3, solve Ksp = s(C + 2s)^2 for molar solubility s (if C ≫ s, s ≈ Ksp/C^2).
How to calculate solubility of calcium iodate?
In pure water, let s be molar solubility: Ksp = s(2s)^2 = 4s^3, so s = (Ksp/4)^(1/3); convert to g/L by multiplying s by the molar mass of Ca(IO3)2.
How to calculate the concentration of iodate from calcium iodate in 0.1 kio3?
With [IO3−]0 = 0.1 M from KIO3, the iodate contributed by dissolving Ca(IO3)2 is 2s where s solves Ksp = s(0.1 + 2s)^2 (if 0.1 ≫ s, [IO3−] from Ca(IO3)2 ≈ 2Ksp/(0.1)^2).
How to calculate the concentration of iodate from calcium iodate in pure water?
For Ca(IO3)2 in water, [IO3−] = 2s with s = (Ksp/4)^(1/3), so [IO3−] = 2(Ksp/4)^(1/3) assuming activities ≈ concentrations.
How to find molar solubility of calcium iodate?
Write Ksp = [Ca2+][IO3−]^2; in pure water s = (Ksp/4)^(1/3), and in a solution with iodate C (common ion) s is given by Ksp = s(C + 2s)^2 ≈ Ksp/C^2 when C ≫ s.